Solving Algebraic Expressions: A Step-by-Step Guide

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Hey there, algebra enthusiasts! Ready to dive into some cool math problems? Today, we're going to tackle expressions like (a+2x2βˆ’2)2(a + 2x^2 - 2)^2 and learn how to find their values when we plug in some numbers. Don't worry, it's not as scary as it looks! We'll break it down step by step, making sure everyone can follow along. This guide will help you understand how to solve these types of problems and give you the confidence to ace your algebra assignments. Let's get started, guys!

Understanding the Basics of Algebraic Expressions

Alright, before we jump into the main event, let's get a quick refresher on what algebraic expressions are all about. Basically, an algebraic expression is a combination of numbers, variables (like x or a), and mathematical operations (+, -, *, /). The goal is often to simplify these expressions or find their value when you know what the variables are. In our examples, we'll be given specific numbers to substitute for the variables, making the expression solvable. Understanding the order of operations is also a crucial part. Remember PEMDAS/BODMAS: Parentheses/Brackets, Exponents/Orders, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right). That's the golden rule to solving these expressions correctly. Mess up the order, and you'll end up with a wrong answer – not what we want, right?

Let's take a closer look at our target expression: (a+2x2βˆ’2)2(a + 2x^2 - 2)^2. This expression tells us to do a few things. First, we have to deal with what's inside the parentheses. We will encounter variables a and x, and we must apply the order of operations inside the parenthesis. Specifically, we'll have an exponent (the x2x^2 part), which we need to calculate before we can add or subtract. Then, after all of that is done, we have an exponent on the entire expression – the 'squared' part. That means we multiply whatever we get from inside the parentheses by itself. So, once we know the values of a and x, we'll be able to plug them in, solve what's inside the parentheses, and then square the result. Sounds like fun, eh? Trust me, practice is what makes perfect, so let's get our hands dirty and solve some examples!

Solving the First Example: (5 + 7 * 3Β² - 2)Β²

Okay, time for our first problem: (5+7imes32βˆ’2)2(5 + 7 imes 3^2 - 2)^2. Here's how we can crack this one. First, we look at the expression inside the parentheses: (5+7imes32βˆ’2)(5 + 7 imes 3^2 - 2). Remember PEMDAS/BODMAS? This tells us the order of operations. Let's break it down step by step. We start with the exponent: 323^2 (3 squared) which equals 9. Great! Now our expression becomes: (5+7imes9βˆ’2)(5 + 7 imes 9 - 2). Next up, multiplication: 7imes9=637 imes 9 = 63. Now we have: (5+63βˆ’2)(5 + 63 - 2). Finally, we do the addition and subtraction from left to right: 5+63=685 + 63 = 68, then 68βˆ’2=6668 - 2 = 66. So, what's inside the parentheses simplifies to 66. But we aren't done yet, guys! We have that little 'squared' symbol outside the parentheses. This means we have to square the entire result, so we do 66266^2, which equals 4356. Boom! We've solved the first example. See? Not so bad, right? The key here is to carefully follow the order of operations and take it one step at a time. Don't rush! The first time can be tricky, but with a little practice, you'll nail it.

So, for (5+7imes32βˆ’2)2(5 + 7 imes 3^2 - 2)^2, the answer is 4356.

Breaking Down the Steps:

  1. Focus on the Parentheses: Start by identifying what's inside the parentheses: (5+7imes32βˆ’2)(5 + 7 imes 3^2 - 2).
  2. Handle Exponents: Solve the exponent first: 32=93^2 = 9. The expression becomes: (5+7imes9βˆ’2)(5 + 7 imes 9 - 2).
  3. Multiplication: Perform the multiplication: 7imes9=637 imes 9 = 63. The expression becomes: (5+63βˆ’2)(5 + 63 - 2).
  4. Addition and Subtraction: Perform addition and subtraction from left to right: 5+63=685 + 63 = 68, then 68βˆ’2=6668 - 2 = 66.
  5. Square the Result: Finally, square the result: 662=435666^2 = 4356.

Solving the Second Example: (4 + 2 * 8Β² - 2)Β²

Alright, let's tackle the second part of our challenge: (4+2imes82βˆ’2)2(4 + 2 imes 8^2 - 2)^2. This one looks very similar to the first, so let's apply the same logic and see how it goes. Again, the order of operations is going to be our best friend here. First, deal with the expression inside the parentheses. Then, as always, PEMDAS/BODMAS, which means we start with the exponent: 828^2 (8 squared) which equals 64. Now, our expression simplifies to: (4+2imes64βˆ’2)(4 + 2 imes 64 - 2). Next, perform the multiplication: 2imes64=1282 imes 64 = 128. So, we're left with: (4+128βˆ’2)(4 + 128 - 2). Now, we perform addition and subtraction from left to right: 4+128=1324 + 128 = 132, and then 132βˆ’2=130132 - 2 = 130. Awesome! We've simplified the inside of the parentheses to 130. The very last step is to square the final answer, giving us 1302=16900130^2 = 16900. And that, my friends, is how we solve the second example.

So, for (4+2imes82βˆ’2)2(4 + 2 imes 8^2 - 2)^2, the answer is 16900.

Breaking Down the Steps:

  1. Focus on the Parentheses: First, what's inside the parentheses: (4+2imes82βˆ’2)(4 + 2 imes 8^2 - 2).
  2. Handle Exponents: Solve the exponent: 82=648^2 = 64. The expression becomes: (4+2imes64βˆ’2)(4 + 2 imes 64 - 2).
  3. Multiplication: Perform the multiplication: 2imes64=1282 imes 64 = 128. The expression becomes: (4+128βˆ’2)(4 + 128 - 2).
  4. Addition and Subtraction: Perform addition and subtraction from left to right: 4+128=1324 + 128 = 132, and then 132βˆ’2=130132 - 2 = 130.
  5. Square the Result: Finally, square the result: 1302=16900130^2 = 16900.

Tips for Success in Solving Algebraic Expressions

Okay, we've solved two examples, and hopefully, you're feeling more confident. But how do you get even better at this? Well, here are a few tips and tricks to help you on your algebraic journey. First, practice, practice, practice! The more you solve, the more comfortable you'll get with the process. Start with simpler problems, and then gradually move to more complex ones. Make sure you understand the order of operations inside and out. PEMDAS/BODMAS is your best friend here. Write down each step clearly. Don't try to do too much in your head, at least not at first. This helps you avoid mistakes and makes it easier to check your work. Take your time. Rushing leads to errors. Double-check your answers. It’s always a good idea to go back and review each step. Did you remember to square the result? Did you add and subtract in the correct order? Check for any common mistakes. Maybe you forgot to multiply before adding or subtracting. If you're struggling, don't be afraid to ask for help! Your teachers, tutors, or classmates are there to help you get a better understanding. Don't be discouraged if you don't get it right away. Algebra takes time and effort.

Conclusion: Keep Practicing!

Well, guys, that wraps up our lesson on solving algebraic expressions. We've seen how to solve problems by following the order of operations. Remember, practice is key. Keep at it, and you'll get better and better with each problem you solve. Math can be fun, and with a little effort, you can conquer any algebraic expression that comes your way. Keep practicing, and always remember to double-check your work! Happy solving!